Question

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Do middle term split of :-
$1.) \: {2x}^{2} - x + \frac{1}{8} = 0$

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Answer 1

Answer:

$$ The \sqrt{64} \ \times \ 2 \ \times \ 4^3 \ = \ 1024 $$

{\displaystyle The{\sqrt {64}}\ \times \ 2\ \times \ 4^{3}\ =\ 1024}$$ The \sqrt{64} \ \times \ 2 \ \times \ 4^3 \ = \ 1024 $$

{\displaystyle The{\sqrt {64}}\ \times \ 2\ \times \ 4^{3}\ =\ 1024}

$$ \sqrt{64} \ = \ 8 $$

{\displaystyle {\sqrt {64}}\ =\ 8}

$$ 3x_2 \ \times \ 2x_3 $$

{\displaystyle 3x_{2}\ \times \ 2x_{3}}

$$ 4^2 \ \times \ 4^3 \ = 4^5 $$

This is a shorthand way of saying:

(4 x 4) x (4 x 4 x 4) = (4 x 4 x 4 x 4 x 4)

or

16 x 64 = 1024.

{\displaystyle 4^{2}\ \times \ 4^{3}\ =4^{5}}

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