Question

$\huge{\mathtt{\underline{question}}}$

In a flight of 600 km, an aircraft was slowed due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. Find the original duration of the flight.
(Class 10, Chapter 4 - Quadratic equations)

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Answer 1

$\huge\mathfrak\green{hello} </p><p>$

$\huge\mathfrak\orange{answer = 1hrs}$

$\huge\mathfrak\blue{ step \: by \: step \: explanation}</p><p></p><p>tex]$

By Assuming a as speed of aircraft So reduced speed be -:

$\small\mathfrak\red{(a - 200)km hr}$

DURATION OF ORIGINAL SPEED BE -(i)

$\huge\mathfrak\green{(600 \div a)hr}$

REDUCED SPEED BE.(ii)

600 - 600 =1/2

a-200 a

=>After making denominator same we get

120000 = 1

a²-200a 2

=>

a²-200a-240000=0

Now factorize this

So,

a²-600a+400a-240000

(a-600) (a+400)

so a=600,-400

=> a =600 has speed cant be in negative

SO FROM

=>( 600/a)hr

=>(600/600)hr

=>1hr

$\huge\mathfrak\orange{hope u got it }$

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