Question

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A farmer connects an internal pipe of diameter 20 cm from a canal into a cylindrical tank of internal diameter 10 m and 2 m deep. If the water flows through the pipe at the rate of 4 km per hour, in how much time will the tank be filled completely?​

Answer 1

Volume of cylindrical tank = πr^2h

= 22/7 * 10/2 * 10/2 * 2

= 1100 / 7 m^3

Radius of pipe = 10 cm = 0.1 m

Speed = 4 km / hour = 4000m / hr

Let length of water column be 'x' meter

Volume of water column = 1100/7 m^3

= πr^2h

= 22/7 * 0.1 * 0.1 * x

= 0.22x/7

1100/7 = 0.22x/7

1100 = 0.22x

1100/0.22 = x

5000 = x

Length of water column = 5000 m = 5km

Time = Distance / Speed

Time = 5 / 4

= 1.25 hrs

= 1 hours and 15 minutes


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