Question

$\huge{Qu€stion}$​

Answer 1

Answer:

${ \boxed{\boxed{\begin{array}{cc} \bf \to \: given : \\ \\ \pink{ \underline{ \bf \: in \: \: planet :A}} \\ \\ \hookrightarrow \sf \:weight\ \: \: \: W_A = 250 \:N \\ \\ \to \: \bf \: gravity \: \: = g_{A} = 9.8 \: m {s}^{ - 2} \\ \\ \green{ \underline{ \bf \: in \: planet :B }} \\ \\ \hookrightarrow \sf \: \: weight \: \: W_B = 200 \: N \\ \\ \red{ \to \bf \: gravity \: = g_{B } = to \: find}\\ \\ \\ \boxed{ \sf \: let \: \: mass \: of \: the \: body \: \: = m} \\ \\ \red{ \sf{we \: know \: that : }} \\ \\ \orange{ \boxed{\bf \: W = mg}} \\ \\ \sf \: so \\ \\ \bf \: W_A = mg_{A} \: \: \: - - - (1) \\ \\ \bf \: W_B = mg_{B} \: \: \: - - - (2) \\ \\ \\ \sf \: eqn.(2) \div \: eqn.(1) \\ \\ \bf \: \frac{W_B}{W_A} = \frac{m \: g_{B}}{m \: g_{A}} \\ \\ \implies \bf \: \frac{200}{250} = \frac{g_{B}}{9.8} \\ \\ \bf \implies \: g_{B} = \frac{200 \times 9.8}{250} \\ \\ \therefore \: \bf \: g_{B} = 7.84 \: m {s}^{ - 2} \\ \\ \sf \: (answer) \end{array}}}}$

Answer 2

$\huge\sf\fbox\purple{ ★ Solution ★}$

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°°° Explanation °°°

To find zero of the polynomial, p(x)=0

(i) If p(x)=x+5=0 then x=−5, i.e. −5 is the zero.

(ii) If p(x)=x−5=0 then x=5, i.e. 5 is the zero.

(iii) If p(x)=2x+5=0 then x= 2

−5 , i.e. 2−5 is the zero.

(iv) If p(x)=3x−2=0 then x= 32

, i.e. 32 is the zero.

(v) If p(x)=3x=0 then x=0, i.e. 0 is the zero.

(vi) If p(x)=ax=0 then x=0, i.e. 0 is the zero.

(vii) If p(x)=cx+d=0 then x= c−d

, i.e. c −d

is the zero.