Question

The Power generated in a resistor of 5 K-² with a current flow of 50 mA is

9) 12.5 w b) 250 W c),1.25 MW

d) 2.5 MW​

Answer 1

Answer:

2. 5 MW is the answer

Explanation:

hope it helps you

Answer 2

Answer:

250w

Explanation:

p=vi

5=v×50ma

v=(5×10^6)/50

v=