Question

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The sides of a triangle are in the ratio of 12: 17: 25 and its perimeter is 540cm. Find its area.






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Answer 1

Answer:

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✏Solution⬇

⇒Let x be common ratio

∴ Sides of triangle will be: 12x,17x and 25x

⇒Perimeter =540 cm(given)

⇒12x+17x+25x=540 cm,

⇒54x=540 cm

⇒x=10 cm

∴ Sides of triangle: a=120,b=170,c=250 cms

⇒2S=540

⇒S=270 cm

$A = \sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{270(270 - 120)(270 - 170)(270 - 150)cm\2}$

$A = \sqrt{270 \times 150 \times 20cm2}$

Hope it helps you..

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Answer 2

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The sides of a triangle are in the ratio of 12: 17: 25 and its perimeter is 540cm. Find its area.

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