Question

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If the perimeters of two similar triangles ABC and DEF are 50 cm and 70 cm respectively and one side of ∆ABC = 20 cm, then find the corresponding side of ∆DEF.




➳ REQUIRED GOOD ANSWER​

Answer 1

Answer:

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Answer 2

$\huge\sf\underline\blue{Your \: Answer}$

Given:-

Perimeters of two similar triangles are 50 cm and 70 cm.

Therefore, ratio of their corresponding sides

$= \frac{50}{70} = \frac{5}{7}$

Now from ∆ABC and ∆DEF, we have:

$\small\sf \frac{AB}{DE} = \frac{5}{7} ⇒ \frac{20}{DE} = \frac{5}{7}$

$⇒\small\tt\red{DE} = \frac{20 \times 7}{5} = 28 \: cm$

$\small\tt\fbox\green{Thus, the \: side \: of \: ∆DEF \: corresponding to \: the \: side \: 20 \: cm \: of \: ∆ABC \: is \: 28 \: cm}$