Math, asked by as3801504, 1 month ago


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 {2}^{x  + y}  \times  {3}^{x - y}  =  \sqrt{8}   \\ then \: the \: value \: of \: y \: is \:  \\ a) \frac{1}{2} \:  \:  \:  \:  \:   \: b) \frac{3}{2}  \:  \:  \:  \: c)0 \:  \:  \: d ) \: none \: of \: these
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Answers

Answered by Diliptalapda
1

Step-by-step explanation:

\mathtt\red{ \implies {2}^{x + y}  =  {2}^{x - y} =  {2}^{ \frac{3}{2} }  }

\mathtt\red{ \implies \: x + y =  \frac{3}{2} \:  \:  \:  \:  \:  \:  \: .(i) }

\mathtt\red{ \implies \: and \: x - y =  \frac{3}{2} \:  \:  \:  \:  .. (ii) }

\mathtt\red{on \: solving \: eq(i) \: and \: eq(ii).we \: get}

\mathtt\red{x =  \frac{3}{2}  \: and \: y = 0}

hope it helpful for you.

thanks.

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