Question

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If HCF of 210 and 55 is expressible in form of 210×55+55y. Find y​

Answer 1

Answer:

Since now the remainder is zero, therefore divisor at this stage, that is 5, is the HCF of 210 and 55. Comparing equation (vi) with the given equation: 5=210×5+55y, we get, y=−19. This is the required solution.

Step-by-step explanation:

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