Question

$\huge\red{Question-}$
Answer the above attachment...
(Trash answer will be reported)​

Answer 1

Let ,

1 Banana = B

1 Pineapple = P

1 Cherry = C

1 Orange = O

A/c to 1st condition ,

2 Bananas + 2 Bananas + 2 Bananas = 60

➠ 2 B + 2 B + 2 B = 60

➠ 6 B = 60

➠ B = 10

So , 1 Banana = 10

A/c to 2nd condition ,

2 Bananas + ( 1 Pineapple + 2 Cherries ) + ( 1 Pineapple + 2 Cherries ) = 40

➠ 2 B + 2 P + 4 C = 40

➠ 2 ( 10 ) + 2 P + 4 C = 40

➠ 20 + 2 P + 4 C = 40

➠ 2 P + 4 C = 20

➠ P + 2 C = 10 ___ (1)

A/c to 3rd condition ,

( 1 Pineapple + 2 Cherries ) + 2 Oranges + 2 Oranges = 26

From (1) , we have ( P + 2 C = 10 )

➠ ( P + 2 C ) + 2 O + 2 O = 26

➠ 10 + 4 O = 26

➠ 4 O = 16

➠ O = 4

1 Orange = 4

A/c to 4th condition ,

( 1 Pineapple + 2 Cherries ) + 2 Oranges - 2 Cherries = 14

➠ ( P + 2 C ) + 2 O - 2 C = 14

➠ P + 2 O = 14

➠ P + 2 ( 4 ) = 14

➠ P + 8 = 14

➠ P = 6

1 Pineapple = 6

Sub. P value in (1) ,

➳ ( 6 ) + 2 C = 10

➳ 2 C = 4

➳ C = 2

1 Cherry = 2

Our required 5th one ,

➙ ( 3 Bananas + 1 Cherry ) + 1 Pineapple × ( 1 and ¹/₂ Orange )

➙ ( 3 B + 1 C ) + 1 P × ( ³/₂ O )   [ ∵ 1 + ¹/₂ = ³/₂ ]

➙ ( 3 ( 10 ) + 1 ( 2 ) ) + 1 ( 6 ) × ³/₂ ( 4 )

➙ ( 30 + 2 ) + 6 × 6

Apply BODMAS rule ,

➙ 32 + 36

➙ 68  $\pink{\bigstar}$

68 is the required answer

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Answer 2

Answer:

Required Answer :-

Let us assume

Banana = b

Pineapple = p

Orange = o

Cherry = c

Now,

In 1

$\sf \: 2b + 2b + 2b = 60$

$\sf \: 6b = 60$

$\sf \: b = \dfrac{60}{6}$

$\sf \: b = 10$

Value of 1 one banana = 10

In 2

$\sf \: 2(10) + p + 2( c) + p + 2(c) = 40$

$\sf \: 20 + p + 2c + p + 2c = 40$

$\sf \: 20 + 2p + 4c = 40$

$\sf \: 2p + 4c = 40 - 20$

$\sf \: 2p + 4c = 20$

Dividing both side by 2

$\sf \: p + 2c = 10$

In 3

$\sf \: p + 2c + 2o + 2o = 26$

$\sf \: 10 + 2o + 2o = 26$

$\sf \: 2o + 2o = 26 - 10$

$\sf \: 4o = 26 - 10$

$\sf \: 4o = 16$

$\sf \: o \: = \dfrac{16}{4}$

$\sf \: o = 4$

So,

Till now we have

Value of 1 banana = 10

Value of 1 orange = 4

In 4

$\sf \: p + 2c \: + 2(10) - 2c= 14$

$\sf \:p + 2o = 14$

$\sf \: p + 2(4)= 14$

$\sf \: p + 8 = 14$

$\sf \: p = 14 - 8$

$\sf \: p = 6$

Now

For cherry

$\sf \: p + 2c = 10$

$\sf \: 6 + 2c = 10$

$\sf \: 2c = 10 - 6$

$\sf \: 2c = 4$

$\sf \: c \: = \dfrac{4}{2}$

$\sf \: c = 2$

So,

In 5

$\sf \: 3(10) + 2 + 6 \times 4 + 2$

$\sf \: 30 + 2 + 36$

$\sf \: 32 + 36$

$\sf \: 68$