Four persons started to do a work together. 'A' works only in starting two days after that B, C and D works alternately starting from B. Ratio of time taken by A, B, C and Dif they work alone is 4: 3: 2: 5. If the work is completed in 12 days then in how many days A and Ccan complete the work if they work together?
Answers
Step-by-step explanation:.
A, B, C and D worked for 2 days together after that A leave and B, C and D worked alternatively for 10 days starting from B
∴ B worked for 4 days, C for 3 days, and D for 3 days.
Total days A worked = 2
Total days B worked = 4 + 2 = 6
Total days C worked = 3 + 2 = 5
Total days D worked = 3 + 2 = 5
Let, their alone time to complete the work is 4x, 3x, 2x and 5x
respectively.
∴ (2/4x) + (6/3x) + (5/2x) + (5/5x)= 1
⇒ (30+120+150+60) / 60 = 1
⇒ = 360/60 = 6
‘A’ can complete the work in 4 × 6 = 24 days
‘C’ can complete the work in 2 × 6 = 12 days
Required time = (12×24) / (12+24)
= (12×24)/36 = 8 days
hope it helps you
Answer:
A, B, C and D worked for 2 days together after that A leave and B, C and D worked alternatively for 10 days starting from B
∴ B worked for 4 days, C for 3 days, and D for 3 days.
Total days A worked = 2
Total days B worked = 4 + 2 = 6
Total days C worked = 3 + 2 = 5
Total days D worked = 3 + 2 = 5
Let, their alone time to complete the work is 4x, 3x, 2x and 5x
respectively.
∴ (2/4x) + (6/3x) + (5/2x) + (5/5x)= 1
⇒ (30+120+150+60) / 60 = 1
⇒ = 360/60 = 6
‘A’ can complete the work in 4 × 6 = 24 days
‘C’ can complete the work in 2 × 6 = 12 days
Required time = (12×24) / (12+24)
= (12×24)/36 = 8 days