Question

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Question➡️ A scooter was bought at rupees 42,000 .Its value depreciated at the rate of 8% per annum. Find its value after 1 year.

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NOTE:-

✔ No useless answer

Answer 1

Answer:

Rs. 38640

Step-by-step explanation:

42000 × (100-8)/100

=> 42000 × 92/100

=> 38640

So, the value of scooter after 1 year will be 38640

Answer 2

Answer:

Step-by-step explanation:

The time Period after which interest is added each time to form a new principal is called the conversion period and the interest so obtained is called a compound interest.

 

If the conversion period is 1 year then the interest is said to be compounded annually.

 

The main difference between the simple interest and compound interest on a certain sum is that in the case of simple interest the principal remains constant throughout wheras in the case of compound interest it goes on changing periodically.

 

The above formula is the interest compounded annually

A= P(1+r/100)^n

 

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Given:

 Principal (P) =₹ 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years

Amount (A)  = P(1-R/100)^n

[Value depreciated]

A= 42000(1-8/100)¹

A=42000(1-2/25)

A= (42000×23)/25

A= 1680× 23

A= ₹ 38640

Hence, the value of the scooter after one year = ₹ 38640.

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