Question

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➠ Veena’s mother gave her Rs. 2 xy2and her father gave her Rs. 7 (xy2+ 3). She spent Rs (3 + 4 xy2) on her shopping. Algebraically how much money is left with her?
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Answer 1

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Answer 2

Step-by-step explanation:

Given ;

Veena's mother gave = Rs. 2xy² .

Veena's father gave = RS. 7(xy² +3).

She spent = Rs . (3+4xy² ).

Find : How much money left with veena .

Solution ;

Total money veena has =

( Money given by mother + Given by father )..

=> 2xy² + 7 ( xy² + 3)

= 2xy² + 7xy² + 21

= 9xy² + 21 .( is the total money ).

Now, she spent = 3+4 xy².

Left money with veena = ( Total money - spent )

= (9xy² + 21 ) - (3 + 4xy²)

= 9xy² - 4xy² +21 - 3

= 5xy² + 18 . ( ans )...

Hence the money left with veena = 5xy² + 18 .

Hope ! it's helpful...