Question

$\huge\star\underline\mathrm\purple{Question}$ Kunal built a cubical water tank with lif for his house, with each other edge 1.5m long.he gets the outer surface of the tank excluding the base covered with square tiles of side 25cm. find how much he would spend for the tiles, if the cost of the tiles is Rs 540 per dozen​

Answer 1

Answer:

1.5 m = 150 cm

150 cm x 6 = 900 cm.

900 cm / 25 cm = 36.

If a dozen of tiles cost rs. 540,

Then 36 = 3 dozen.

1 dozen cost rs. 540.

3 dozen cost rs. 540 x 3 = 1620.

Step-by-step explanation:

$\bold\blue{Hope~It~Help~You.}$

Answer 2

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$\huge\star\underline\mathrm\purple{Question}$

Kunal built a cubical water tank with lif for his house, with each other edge 1.5m long.he gets the outer surface of the tank excluding the base covered with square tiles of side 25cm. find how much he would spend for the tiles, if the cost of the tiles is Rs 540 per dozen

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$\huge\star\underline\mathrm\purple{Solution}$

Leaving aside the base, the remaining five faces of the tank are to be covered with tiles.

$lenght \: of \: each \: edge \: of \: the \: tank = 1.5m = (1.5 \times 100)cm \\ = 150cm.$

$surface \: area \: of \: each \: face = (150 \times 150) {cm}^{2}$

$total \: surface \: area \: of \: five \: faces \: to \: be \: covered \: with \: tiles = (5 \times 150 \times 150) {cm}^{2}$

$area \: of \: each \: square \: tilr = (25 \times 25) {cm}^{2}$

$number \: of \: tile \: required = \frac{surface \: area \: of \: five \: faces}{area \: of \: each \: tile} \\ = ( \frac{5 \times 150 \times 150}{25 \times 25} = 180.$

$cost \: of \: 12 \: tiles \: = Rs \: 540$

$cost \: of \: 1 \: tile \: = \: Rs \: ( \frac{540}{12} ).$

$cost \: of \: 180 \: tiles = rs( \frac{540}{12} \times 180) = Rs \:8100$

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