Question

$\huge\tt\fcolorbox{cyan}{plum}{♚ᑫᑌᗴՏTIOᑎ࿐}$



50 identical circular plates are placed one above the other to form a solid cylinder. For each plate, diameter = 21 cm and thickness = 1.5 cm.

Find :

(1) curved surface area of the cylinder formed.

(ii) volume of the cylinder fomred.


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Need step by step solution✌​

Answer 1

Answer:

answer :

50 circular plates

diameter of plate =14cm

Radius of plate = d/2=

14/2

=7cm

thickness =0.5cm

→ Height of the cylinder = No. of plates × thickness of plate

=50×0.5

=25cm

→ total surface Area = curved surface + 2 × area of base

=2πr.h+2×πr²

=2πr(h+r)

=2π×7(25+7)

=2× 22/7×7×32

=1408cm²

hope it helps uh

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have a great day

keep smiling always dear sista ❣️..

Answer 2

$\large{ \textsf{\textbf {\pink {➸ \: \: Question \: :-}}}}$

50 identical circular plates are placed one above the other to form a solid cylinder. For each plate, diameter = 21cm and thickness = 1.5cm.

Find :-

1. Curved surface area of the cylinder formed.
2. Volume of the cylinder formed.

$\large {\textsf{ \textbf {\pink {➸ \: \: Solution \: :-}}}}$

Given :-

• 50 plates each with diameter = 21cm
• Radius = $\sf \cfrac {21}{2}$cm
• Thicknesses of each plate = 1.5cm
• Total thickness of the plates = 1.5cm × 50 = 75cm

$\boxed {\rm \bold \blue {CSA \: of \: a \: cylinder=2\pi rh}}$

$\blue ➸ \: \: \: \sf 2( \cfrac{22}{7} )( \dfrac{21}{2} )(75)$

$\blue ➸ \: \: \: \sf\cancel{ 2} \times \cfrac{22}{7} \times \cfrac{21}{\cancel2} \times 75$

$\blue ➸~~~\sf \cfrac{22 \times 21 \times 75}{7}$

$\blue ➸ \: \: \: \sf \cfrac{34,650}{7}$

$\blue ➸~~~\sf CSA = 4950~cm^2$

$\boxed {\bold \blue{Volume \: of \: a \: cylinder =\pi r^2h} }$

$\blue➸ \: \: \: \sf \cfrac{22}{7} ( \cfrac{21}{2} )( \cfrac{21}{2} )(75)$

$\blue ➸ \: \: \: \sf \cfrac{\cancel{22}}{7} \times \cfrac{21}{\cancel2} \times \cfrac{21}{2} \times 75$

$\blue➸ \: \: \: \sf \cfrac{3,63,825}{14}$

$\blue➸ \: \: \: \sf Volume=25987.5~cm^3$

$\large {\textsf {\textbf \pink {➸ \: \: Know \: more \: :-}}}$

• Volume of cube = $\sf a^3$
• Volume of cuboid = $\sf lbh$
• CSA of cube = $\sf 4a^2$
• CSA of cuboid = $\sf 2h(l+b)$
• LSA of cube = $\sf 6a^2$
• LSA of cuboid = $\sf 2(lb + bh + hl)$

_____________________

@Sita05✨