The least count of a stop watch is 1/5 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The maximum percentage error in the measurement of time will be
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Answer:
Explanation:
Final. Answer :Maximum percentage error in time taken., = 0.8%
Steps:
1) Least count,
At = 0.2s
Time taken to complete 20 oscillations, T = 25 s
No. of Oscillations, N = 20
Percentage error in measurement of time,
AT* 100% = ?
We shall find relative error,
T
t
N
=> ln(T) = ln( t
=> ln(T) = ln(t) - In(N)
AT +0
We get,
t N T =
AT T At t
AT T * 100%
At t * 100%
0.2 25 * 100 = 0.8%
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