Question

$\huge\underline{\bf \orange{Question :}}$

Total mass of an elevater with 80 kg man in it is 1000 kg it is brought to rest over a distance of 16m then during retardation the tension in the supporting cable force exerted by man on the floor is respectively​

Answer 1

Answer:

Explanation:

Solution :

The elevator having an initial upward speed of 8 m/sec is brought to rest within a distance of 16 m.

Hence

v² = u² + 2as

0² = 8² + 2* a * 16

064 +32a

84

...

➡32a = -64

a = -64/32

➡a=-2 m/s²

According to Newton's law

T - mg = ma

➡ T = mg + ma

T =m(g + a)

T = 1000 (9.8 - 2)

= T = 7800 N

Let P be the upward force exerted on the man by the elevator floor. If m be the mass of the man, then

weight of the man acting downward = m

g

84

Upward force on the man = P - m'g.

According to Newton's law

P - m'g = m'a

P = m (a + g)

➡P=80 (-2+ 9.8)

P = 624 N