Question

$\huge \underline \mathfrak \pink{Hey :) \: Questions \: }$



Express each number as a product of its prime factors:
(i) 140
(ii) 156
(iii) 3825
(iv) 5005
(v) 7429


KINDLY SOLVE ALL THE QUES! PLOX​

Answer 1

REQUIRED SOLUTIONS:

Here in this question we have to find product of primes of the given numbers. Product of primes simply means breaking the given numbers into their factors or multiples.

So let's find!

$\rule{300}{2}$

‎ ‎

‎

ANSWER 1

$\begin{array} {c|c}2&140\\\cline{1-2}2&70\\\cline{1-2}5&35\\\cline{1-2}7&7\\\cline{1-2}&1\end{array}$

Hence we can express 140 as:

=> 2×2×5×7

It is also called product of the primes because here we have simplified 140 into its prime factors.

$\rule{300}{2}$

‎ ‎ ‎

ANSWER 2

$\begin{array} {c|c}2&156\\\cline{1-2}2&78\\\cline{1-2}3&39\\\cline{1-2}13&13\\\cline{1-2}&1\end{array}$

Product of primes of 156 are:

=> 2×2×3×13

$\rule{300}{2}$

‎ ‎ ‎

ANSWER 3

$\begin{array} {c|c}3&3825\\\cline{1-2}3&1275\\\cline{1-2}5&425\\\cline{1-2}5&85\\\cline{1-2}17&17\\\cline{1-2}&1\end{array}$

Product of primes of 3825 are:

=> 3×3×5×5×17

$\rule{300}{2}$

‎ ‎ ‎

ANSWER 4

$\begin{array} {c|c}5&5005\\\cline{1-2}11&1001\\\cline{1-2}91&91\\\cline{1-2}&1\end{array}$

Product of primes of 5005 are:

=> 5×11×91

$\rule{300}{2}$

‎ ‎ ‎

ANSWER 5

$\begin{array} {c|c}17&7429\\\cline{1-2}19&437\\\cline{1-2}23&23\\\cline{1-2}&1\end{array}$

Product of primes of 7429 are:

=> 19×17×23

$\rule{300}{2}$

NOTE- Kindly see this answer on web.

Answer 2

Step-by-step explanation:

$\huge \underline \mathfrak \pink{Answer }$

◾◾here is your answer...

✒140 = 2 × 2 × 5 × 7 = 2^2 × 5 × 7

✒156 = 2 × 2 × 3 × 13 = 2^2 × 3 × 13

✒3825 = 3 × 3 × 5 × 5 × 17 = 3^2 × 5^2 × 17

✒5005 = 5 ×7× 11 × 13

✒7429 = 17 × 19 × 23

✿┅═══❁✿ Be Brainly✿❁═══┅✿