Question

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The angle of elevation of the top of a vertical tower PQ from a point X on the ground is 60°. From a point Y, 40 m vertically above X, the angle of elevation of the top Q of tower is 45°. Find the height of the tower PQ and the distance PX. (Use √3= 1.732



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Answer 1

Question:

The angle of elevation off the top Q of a vertical tower PQ from a point X on the ground is 60°. At a point Y, 40m vertically above X, the angle of elevation is 45°. Fnd the length of PQ. (Use √3 = 1.732)

Answer:

Given:

XY = 40m, ∠PXQ = 60° and ∠MYQ = 45°

Let PQ = h

Also, MP = XY = 40m

MQ = PQ - MP

= h - 40

Answer 2

The angle of elevation of the top Q of a vertical tower PQ from a point X on the ground is 60∘. From a point Y, 40m vertically above X, the angle of elevation of the top Q of the tower is 45∘. Find the height of the tower PQ and the distance PX. (Use √3=1.73)

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