English, asked by priyadarsini33, 4 months ago

\huge\underline\mathtt{Question}

нε υη∂εяʂтαη∂ʂ мε вεттεя тнαη αηყoηε εℓʂε нε ıʂ нυят ıғ ı cяყ нε ıʂ мoяε тнαη нα℘℘ყ εvεη ıғ ı נυʂт ʂмılε тнεяε'ʂ ʂoмεтнıηg ıη "∂α∂'ʂ ℓovε"
"ωнıcн ıʂ нαя∂ тo ∂εғıηε" ​

Answers

Answered by Meghana1123
3

Answer:

Given: ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D.

To prove :  

Proof : In ABC,     

       M is the midpoint of AB.                (Given)

                   DM || BC            (Given)

  By converse of midpoint theorem,

                    D is the midpoint of AC  i.e.  AD = DC.

In  AMD  and  CMD,

        AD = DC    (proved above)

       ADM =  CDM    (Each  right angle)

            DM = DM      (Common)

            AMD  CMD      (By SAS)

             AM = CM         (CPCT)

       

  Hence, proved

Answered by Anonymous
3

Answer:

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