Two cubes each of volume 27 cm3 are joined end to end to form a solid. Find the surface area of the resulting cuboid.
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Two cubes each of volume 27 cm³ are joined end to end to form a solid. Find the surface area of the resulting cuboid.
Volume of a cube = 27 cm³
⇒ (Side)³ = (3)³ ∴ Side = 3 cm
Length of resulting cuboid, l = 2 × 3 = 6 cm
Breadth of resulting cuboid, b = 3 cm
Height of resulting cuboid, h = 3 cm
Surface area of resulting cuboid = 2(lb + bh + hl)
= 2(6 × 3 + 3 × 3 + 3 × 6)
= 2(18 + 9 + 18) = 2(45) = 90 cm²
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Volume of one cube, v=27 cm ^3
Therefore, side of a cube s=v 1/3 =27
1/3 =3 cm
Two cubes of the same volume joined together to form a cuboid.
Therefore, the length of cuboid, L=2s=6 cm
Width of cuboid (B) = Height of cuboid (H) =s=3 cm
Surface Area of cuboid,
S.A=2(LB+BH+LH)=2(6×3+3×3+6×3)=2(18+9+18)=90 cm^2
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