Question

Two poles of height 18 m and 28 m stand upright on a plane ground. If the distance
between their feet is 24 m, find the distance between their tops.
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Answer 1

Solution :-

Let AB and CD be two poles

AB = 18 m and

CD = 28 m

Distance between their feet = BC = 24 m

Join AD . Draw AM ⊥ CD.

∴ DM = CD - CM = CD - AB

= 28 m - 18 m

= 10 m

Now, in right ∆ AMD,

${AD}^{2} = {AM}^{2} + {MD}^{2} \: (By \: \: Pythagoras \: \: theorem)\\ \\ {AD}^{2} = {24}^{2} + {10}^{2} \\ \\ {AD}^{2} = 576 + 100 = 676 \\ \\ {AD}^{2} = {26}^{2} \: or \: AD = 26$

Hence, the distance between their tops = 26m