Find the common difference of the A.P. \frac{1}{3 q}, \frac{1-6 q}{3 q}, \frac{1-12 q}{3 q}, \dots.
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Answered by
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Answer:
Given A.P is
3q
1
,
3q
1−6q
,
3q
1−12q
Then,
3q
1
,
3q
1
−
3q
6q
,
3q
1
−
3q
12q
will also be in AP.
Which results in,
3q
1
,
3q
1
−2,
3q
1
−4
It can be seen clearly that the series is decreasing by the quantity (2)
Hence, the common difference is −2
Step-by-step explanation:
hope it helps!
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