Question

$\huge\underline{\overline{\mid\star{\mathrm{\blue{ QUESTION }}\star\mid}}}$
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim?
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m sample bgera neii hu --,--
alle m liza ka piza hu ^_^​

Answer 1

Answer:

Diameter = 2m

Radius = 1m

Therefore, \bot⊥ distance = 1m

Moment of force = 2.0 Nm

Moment of force = Force \times× \bot⊥ distance

2.0 Nm = 25 \times× \bot⊥ distance

2.0 Nm = F \times× 1 m

F = 2 N