Question

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pls solve these 2 question .

4 no and the 5 no .with process pls


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Answer 1

4. I think the answer is -1/ a

5. 64

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Answer 2

4. They are asking the zero of the polynomial i.e polynomial must get zero when a certain value of x is applied to it.

p(x) = 0

ax + 1 = 0

x = -1/a

Option D is the answer

5.

$x + y + z = 12$

${x}^{2} + {y}^{2} + {z}^{2} = 16$

${(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2(xy + yz + xz)$

By applying the given values,

${12}^{2} = 16 + 2(xy + yz + zx)$

$144 - 16 = 2(xy + yz + zx)$

$xy + yz + zx = 64$

Option C is the answer