Figure shows a brick of weight 2kgf
and dimensions 20cm 10cm 5cm placed in three different positions
on the ground. Find the pressure exerted by the brick in each case.
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Answer:
here it is
Step-by-step explanation:
hope it helps ^_^
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Answered by
1
Answer:
Explanation:
given,
force=2kgf
we know that
presure =
CASE 1
area=L×B=20×10=200cm²
presure=F/A=2/200=1/100=00.1
p=00.1kgf/cm²
CASE 2
area =L×B=10×5=50cm²
presure=F/A=2/50=1/25=0.04
presure in case 2=0.04kgf/cm²
CASE 3
area=L×B=20×5=100cm²
presure=F/A=2/100=1/50=0.02
presure=0.02kgf/cm²
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