Question

$if \: 3 \cos\alpha - 4sin \: \alpha = 2 \cos\alpha + \sin \alpha find \: tan \: \alpha$
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Answer 1

Step-by-step explanation:

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Answer 2

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$3cos \alpha - 4sin \alpha = 2cos \alpha + sin \alpha \\ 3cos \alpha - 2cos \alpha = sin \alpha + 4sin \alpha \\ \cos\alpha = 5sin \alpha \\ 1 \div 5 = sin \alpha \div cos \alpha \\ tan \alpha = 1 \div 5$