Question

$if \: {9}^{x} \times {3}^{2} \times ( { {3}^{ \frac{ - x}{2} \: )} }^{ - 2} = \frac{1}{27}$
find the value of x​

Answer 1

Step-by-step explanation:

see the ans above and plz make me brain list

Answer 2

$\huge{ \mathfrak{Solution}}$

$\sf{ \red{9 {}^{x} \times 3 {}^{2} \times 3 {}^{ (\frac{ - x}{ - 2}) {}^{ - 2} } = \frac{1}{27} }}$

$\sf{ = > (3{}^{2} ) {}^{x} \times 3 {}^{2} \times 3 {}^{ \frac{ - 2x}{ - 2} } = \frac{1}{3 {}^{3} } }$

$\sf{ = > 3 {}^{2x} \times 3 {}^{2} \times 3 {}^{x} = 3 {}^{ - 3} }$

$\sf{ = > 3 {}^{2x + 2 +x } = 3 {}^{ - 3} }$

$\sf{ = > 3 {}^{3x + 2} = 3 {}^{ - 3} }$

$\sf{ \therefore{3x + 2 = - 3}}$

$\sf{ = > 3x = - 5}$

$\sf{ \orange{ \boxed{ = > x = \frac{ - 5}{3} }}}$

$\mathcal{ \green{Hence \: the \: answer \: is \: x = \frac{ - 5}{3} }}$

HOPE THIS HELPS YOU TOMODACHI ✌