Question

$if \: (ax^{3} \: + 2) ^{2} = a ^{2} x ^{6} + x ^{3} + 4$
,then find a.
​

Answer 1

$\huge\sf\underline{Solution}$

Step by step explanation:-

(ax³ + 2 )² = a²x⁶ + x³ + 4

(ax³)² + (2)² + 2 (ax³)(2) = a²x⁶ + x³ +4

a²x⁶ + 4 + 4ax³ = a²x⁶ + x³ +4

a²x⁶ + 4 +4ax³ -a²x⁶ -x³ -4 =0

a²x⁶ - a²x⁶ +4 -4 + 4ax³ -x³ = 0

4ax³ - x³ =0

x³(4a -1) =0

4a -1 =$\frac{0}{x³}$

4a - 1 = 0

4a = 1

a = 1/4

Formulaes used :-

(a + b)² = a² + b² +2ab

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Hope u helpful

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