Question

$if \: \: \\ cosec \alpha + cot \alpha + = p \: \: \: \ \\ then \: prove \: that \\ \cos \alpha = p {}^{2} - 1 \div p {}^{2} + 1$

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Answer 1

Step-by-step explanation:(consider 'A' as alpha)

• cosecA+ cotA=p
• 1/sinA+cosA/sinA=p
• 1+cosA=psinA
• squaring both the sides,
• (1+cosA)^=p^(SinA)^
• (1+cosA)^=p^(1-cos)^
• (1+cosA)^=p^(1-CosA)(1+cosA)
• 1+cosA=p^(1-cosA)
• cosA=p^-1/p^+1

Answer 2

refer the answer in the picture........