Math, asked by TbiaSupreme, 1 year ago

[tex] If D=\left|\begin{array}{ccc}2&3&1\\5&-1&2\\7&4&-1\end{array}\right|,

performing R₁₂(-1) on D; then D will become.............,Select Proper option from the given options.

\left|\begin{array}{ccc}-1&3&1\\6&-1&2\\3&4&-1\end{array}\right|

\left|\begin{array}{ccc}2&1&1\\5&-6&2\\7&-3&-1\end{array}\right|

\left|\begin{array}{ccc}-3&4&-1\\5&-1&2\\7&4&-1\end{array}\right|

\left|\begin{array}{ccc}2&3&1\\3&-4&1\\7&4&-1\end{array}\right|
[/tex]

Answers

Answered by luciianorenato
1

Answer:

After performing R_{12}(-1) on D it will become

\left[\begin{array}{ccc}-3&4&-1\\5&-1&2\\7&4&-1\end{array}\right]

Step-by-step explanation:

I think with R_{12}(-1) you are referring to the matrix row operation R_1 \rightarrow R_1+(-1) R_2.

In this case, you have

R_1 \rightarrow R_1+(-1) R_2 = (2,3,1)-(5,-1,2) = (-3, 4, -1)

So the matrix D becomes

\left[\begin{array}{ccc}-3&4&-1\\5&-1&2\\7&4&-1\end{array}\right]

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