[tex] If\left|\begin{array}{ccc}1&2&5\\1 &x&5\\3&-1&2\end{array}\right|
= 0 are......,Select Proper option from the given options.
(a) 2
(b) -2
(c) 5
(d) -5
[/tex]
Answers
Answered by
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Dear Student,
Answer: x = 2 ( option a is correct)
Solution:
= 0
Now Apply some Row elementary operations,to simplify the determinant
Apply R1 -> R1 -R2
= 0
Now expand the determinant for Row 1 (R1)
![0(2x + 5) - (2 - x)(2 - 15) + 0( - 1 - 3x) = 0 \\ \\ - (2 - x)( - 13) = 0 \\ \\ 2 - x = 0 \\ x = 2 0(2x + 5) - (2 - x)(2 - 15) + 0( - 1 - 3x) = 0 \\ \\ - (2 - x)( - 13) = 0 \\ \\ 2 - x = 0 \\ x = 2](https://tex.z-dn.net/?f=0%282x+%2B+5%29+-+%282+-+x%29%282+-+15%29+%2B+0%28+-+1+-+3x%29+%3D+0+%5C%5C++%5C%5C++-+%282+-+x%29%28+-+13%29+%3D+0+%5C%5C++%5C%5C+2+-+x+%3D+0+%5C%5C+x+%3D+2)
So x = 2, for the given Determinant to be zero.
Hope it helps you.
Answer: x = 2 ( option a is correct)
Solution:
Now Apply some Row elementary operations,to simplify the determinant
Apply R1 -> R1 -R2
Now expand the determinant for Row 1 (R1)
So x = 2, for the given Determinant to be zero.
Hope it helps you.
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