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➝If Sinα = 5/12 Then Find the value of Cosα and Tanα
Solution
We Know That
➝Sinα = Perpendicular(p)/Hypotenuse(h) = 5/12
We get
➝Perpendicular(p) = 5 , Base(b) = x and Hypotenuse(h) = 12
To Find Base , we use Pythagoras Theorem
➝h²= b² + p²
Put the value
➝(12)² = b² + (5)²
➝b² = 144 - 25
➝b² = 119
➝b = √(119) = 10.9 ≈ 11
We get
➝Perpendicular(p) = 5 , Base(b) = 11 and Hypotenuse(h) = 12
Now
➝Tanα = p/b = 5/11
➝Cosα = b/h = 11/12
Answer
➝Tanα = 5/11
➝Cosα = 11/12
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