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If (x - 2) is the factor of x^5 - 3x^4 - ax² + ax + 4,
Then x = 2.
We will put the value of x in the given equation and equate it to zero.
=> (2)^5 - 3(2)^4 - a(2)² + a(2) + 4 = 0
= 32 - 3(16) - 4a + 2a + 4 = 0
= 32 - 48 + 4 - 2a = 0
= - 12 = 2a
= a = -12/ 2
= a = -6
______________________________
I hope it helped.
Thank You!
______________________________
If (x - 2) is the factor of x^5 - 3x^4 - ax² + ax + 4,
Then x = 2.
We will put the value of x in the given equation and equate it to zero.
=> (2)^5 - 3(2)^4 - a(2)² + a(2) + 4 = 0
= 32 - 3(16) - 4a + 2a + 4 = 0
= 32 - 48 + 4 - 2a = 0
= - 12 = 2a
= a = -12/ 2
= a = -6
______________________________
I hope it helped.
Thank You!
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