Question

$if \: x =3 + 2 \sqrt{2} \\ then \: find \: the \: value \: of \: \sqrt{x}$
give the answer fast................

Answer 1

Answer:

√2 + 1

Step-by-step explanation:

Given: x = 3 + 2√2

Then,

$=> \sqrt{x} =\sqrt{3 + 2\sqrt{2}}$

$=>\sqrt{2 + 1 + 2\sqrt{2 * 1}}$

$=>\sqrt{(\sqrt{2}+1)^2}$

$=>\sqrt{2} + 1$

Hope it helps!

Answer 2

Given: x = 3 + 2√2

Then,

⇒ √x = √3 + 2√2

         = √2 + 1 + 2√2 * 1

         = √(2 + 1)²

         = √2 + 1.