Math, asked by rajatsharma5049, 11 months ago


if \: x \: is \: a \: posible \: real \: number \: then \: what \: is \: value \: of \:  \sqrt{4 \sqrt{3 \sqrt{ {x}^{2} } } }

Answers

Answered by GeniusYH
0

Answer:


Step-by-step explanation:


\sqrt{4\sqrt{3\sqrt{x^{2}} } }\\=> \sqrt{4\sqrt{3x}}\\\\=> \sqrt{4} \sqrt[4]{3} \sqrt[4]{x}

Approximately Fourth root of 3 = 1.3161

So 2(4√3) = 2.63215


Hence the answer is

(2.63215)\sqrt[4]{x}




Hope my answer helps you.


Harith

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