Question

$if x= \sqrt{3 } + \sqrt{2} \div \sqrt{3} - \sqrt{2} and \: y = \sqrt{3} - \sqrt{2} \div \sqrt{3} + \sqrt{2} \: find \: {x + y}^{2}$
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Answer 1

x=√3+√2÷√3-√2

x=(√3+√2).(√3-√2)÷(√3-√2)(√3-√2)

x=3-3√2+√3√2-2÷1

x=1-3√2+√3√2÷1

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