Question

$if \: y \alpha 1 \div {x}^{2} and \: x = 2 \: when \: y = 9 \: find \: y \: when \: x = 3$
some one explain in step ​

Answer 1

$if \: y \alpha 1 \div {x}^{2} \implies x^{2}y = k\:--(1)$

$i) Substitute \: x = 2 , \:y = 9 \: in \: Equation \:(1),\\we \:get$

$k = 2^{2} \times 9$

$\implies k = 36 \:--(2)$

$Now, substitute \: y = 9 ,k = 36 \\in \: Equation \:(1), \:we \:get$

$x^{2} \times 9 = 36$

$\implies x^{2} = \frac{36}{9}$

$\implies x^{2} = 4$

$\implies x = \sqrt{4}$

$\implies x = 2$

Therefore.,

$\red { Required \:value \: x} \green { = 2}$

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