Question

$if \ \:y = sec \: x \: then \: find \: \frac{dy}{dx}$
​

Answer 1

Here is ur answer:

$\frac{dy}{dx} = \frac{d}{dx} (sec \: x) = \frac{d}{dx} ( \frac{1}{cos \: x} )$

$\frac{dy}{dx} = \frac{cosx. \frac{d}{dx}(1) - . \frac{d}{dx}(cosx) }{ {cos}^{2}x }$

$= \frac{0 - ( - sinx)}{ {cos}^{2}x }$

$= \frac{sinx}{ {cos}^{2} x}$

$= \frac{sinx}{ {cos}^{2}x } . \frac{1}{cosx}$

= tanx secx

Answer 2

Explanation:

goo with. my attachment plss❤❤

answer is in my attachment✌✌

mind my handwriting ....xD