Question

${In \: the \: figure,\: ABC \: is \:a \:triangle \:and \: O \:is \: a \:point \: in \: it. \: OP \: and \: OQ \: are \: drawn \: perpendicular \: to \: the \: sides \: AB \: and \: BC \: respectively. \: If \: Angle \:B \: = \: 65°,\: find \: Angle \:POQ.}$​

Answer 1

Answer:

∠POQ = 115°

Step-by-step explanation:

here, POQB is a quadrilateral and sum of all angles of quadrilateral is 360°.

∴ ∠BPO + ∠POQ + ∠OQB + ∠QBP = 360°

⇒ 90° + ∠POQ + 90° + 65° = 360°    [Perpendicular makes an angle of 90° on that side]

⇒ ∠POQ = 360° - 245°

⇒ ∠POQ = 115°

hope it will help you.

Answer 2

ɪ ᴡᴀɴɴᴀ ɢᴏᴛ ᴩᴏɪɴᴛꜱ..

In elementary geometry, the property of being perpendicular (perpendicularity) is the relationship between two lines which meet at a right angle (90 degrees). The property extends to other related geometric objects. A line is said to be perpendicular to another line if the two lines intersect at a right angle.