Question

$\int\limits_0^\pi\:cos\:x\: dx$

Answer 1

HELLO DEAR,

GIVEN:- $\bold{\int\limits_0^\pi cosx\,dx}$

we integration of cos.dx = sinx

therefore, $\bold{\int\limits_0^\pi cos\,dx = [sinx]_0^\pi}$

$\bold{\implies sin\pi - sin0}$

$\bold{\implies 0 - 0 = 0 }$

I HOPE IT'S HELP YOU DEAR,
THANKS