Question

$is \: \sqrt{x + \frac{1}{x} } = \sqrt{x} + \frac{1}{\sqrt{x} } ??$
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Answer 1

Step-by-step explanation:

$</p><p> \sqrt{x + \frac{1}{x} } = \sqrt{x} + \frac{1}{\sqrt{x} }</p><p>$

On squaring both sides, we have

${( \sqrt{x + 1 \div x}) }^{2} = {( \sqrt{x} + 1 \div \sqrt{x}) }^{2}$

${( {x + 1 \div x}) } = {( {x}+ 1 \div{x} + 2 ) }$

$= > 0 \: is \: never \: equal \: to \: 2.$

Hence this equation is not true.