Question

$\LARGE\color{black}{\colorbox{#FF7968}{Q}\colorbox{#4FB3F6}{u}\colorbox{#FEDD8E}{e}\colorbox{#FBBE2E}{s}\colorbox{#60D399}{t}\colorbox{#FF7968}{i}\colorbox{#FBBE2E}{o} \colorbox{#4FB3F6}{n}}$

1. Calculate the compound interest on 10,000 for 2 years at 7% p.a.
2. Calculate the compound interest on 15,000 for 2 years at 6% p.a.
3. Calculate the amount and the compound interest on 8000 for 3 years at 15% p.a., interest
compounded annually.
4. Harish invests * 12,500 for 2 years at 12% p.a., calculate the amount and the compound interest
that Harish will get after 2 years.
5. Mahesh invests 3000 for 3 years at the rate of 10% p.a. compound interest. Find the amount and
the compound interest that Ramesh will get after 3 years.




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Answer 1

• 1) compound interst is 1664
• 2) compound interst is 854 .
• 3) compound interest is 9261.
• 4) compound interest is 3,180
• 5) compound interest is 3000

Step-by-step explanation:

Answer - 1

we know that,

$\bold{\pink{\underline{\boxed{\bf{Amount=P\left(1+\dfrac{R}{100}\right)^n}}}}} P is principal = Rs.10000R is rate = 7%n is time = 2 yearsPutting the values,[tex]\small\implies \blue{\sf{Amount=10000\left(1+\dfrac{7}{100}\right)^2}}$$\small\implies \purple{\sf{Amount=10000\left(\dfrac{100+7}{100}\right)^2}}$$\small\implies \red{\sf{Amount=10000\times\left(\dfrac{107}{100}\right)^2}} \\ \small\implies \pink{\sf{Amount=10000\times\left(\dfrac{107}{100}\times\dfrac{107}{100}\right)}} \\ \small\implies \purple{\sf{Amount=10000\times\dfrac{107}{100}\times\dfrac{107}{100}}} \\ \small\implies \blue{\sf{Amount=1\cancel{00}\cancel{00}\times\dfrac{107}{1\cancel{00}}\times\dfrac{107}{1\cancel{00}}}}$$\small\implies \green{\sf{Amount=1\times107\times107}}\large\therefore\boxed{\bf{Amount=11,449.}}$