Question

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Solve the quadratic equation x²+7x-60=0 by Quadratic formula method.​​

Answer 1

GIVEN

x² + 7x - 60

Using quadratic formula

$\boxed{ \red { \pmb{x = \frac{ -b±√b²-4ac}{2a}}}}$

Here, a = 1 , b = 7 & c = -60

$\bf \: \: x= \cfrac{ -7± \sqrt{7²-4(1)(-60)}}{2(1)}$

$\bf \: x= \cfrac{-7± \sqrt{49+240}}{2}$

$\bf \: x= \cfrac{ -7±√289}{2}$

Discriminant, b²- 4ac is greater than zero,

• That means there will be two real & distinct roots.

$\bf \: x= \cfrac{ -7±17}{2}$

$\large \boxed{ \bold{ \blue{x= 5 \: \: or \: -12}}}$

Answer 2

x² −7x−60=0

or, x²−12x+5x−60=0

or, x(x−12)+5(x−12)=0

or, (x−12)(x+5)=0

or, x=12,−5.