Question

$\large{ \pink{\mathfrak{ \underline{\overline{\mid \:\: Question:- \:\: \mid}}}}}$

Choose the correct option :

$\sin^2 \theta + \cos^2 \theta = 1$
$\sin^2 \theta + \cos^2 \theta = 2$
$\sin^2 \theta + \cos^2 \theta = 3$
$\sin^2 \theta + \cos^2 \theta = 3$


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Answer 1

$\\⠀⠀\bigstar \:⠀⠀⠀\underbrace\bold{\large\underline{Concept: - }}$

$\sin^2 \theta + \cos^2 \theta = 1$

$\twoheadrightarrow\underline{\boxed{\pmb{\frak{\purple{ Explanation }}}}}\;\bigstar$

By Pythagoras Theorem

${c^2 = a^2 - b^2}$

$\large\frac{a^2+b^2}{c^2}=1$ (Provided in attachment)

$\sin^2 \theta + \cos^2 \theta = 1$

• Hence proved

Answer 2

$\huge\red{\mid{\underline{\overline{\textbf{ANSWER}}}\mid}}$

$\sin^2 \theta + \cos^2 \theta = 1$

$\huge \mathtt \purple{Explanation:-}$

By Pythagoras Theorem

${c^2 = a^2 - b^2}$

$\large\frac{a^2+b^2}{c^2}=1$ (Provided in attachment)

$\sin^2 \theta + \cos^2 \theta = 1$

Hence proved