Question

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4% w/w solution of (NaOH+H2O) .If the density =1.5gm/cc then find out

¡) Molarity(M)

¡¡)molality(m)

¡¡¡)mole fraction(X)

¡v)Normality(N)

V)Strength(S)
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Answer 1

Helloooooooooo Grandpa Max!!

→ 4% W/W means 4 g(NaOH + H20) in 100ml solution.

now

1) Molarity

→( 4/40) * (1.5/100) *1000

→ 1.5

2) Morality

→{ M/(1000d - M mb) } * 1000

→ {1.5/(1000*1.5 - 1.5*40)} * 1000

= 150 / 144

where, mb = mass of solute

3) Normality

→ M × 2

= 1.5 * 2 = 30

4) mole fraction

→ nb/ (nb + na)

=( 4/40) ÷ (4/40 + 96/18)

wt of solvent (100-4)=96

where, nb = moles of solute

na= moles of solvent

put the values bro... m so lazy

5) Strength

→ w/V * 10

= (4/100)*10 for solute
I'm not sure bout this..

#Jaihind

Answer 2

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