Question

$\large \red✯ \large\mathfrak \red{Question}$
A student took the least count of a vernier calliper as 0.01 mm instead of 0.01 cm and found that the length of a copper rod was 4.909 cm. If one M.S.D. = 1 mm, then find
1) the main scale reading
2) the vernier coinciding division
3) the correct length of the rod
$\large\green✯ \large \sf \pmb {\green{No \: Spam}}$
$\large\pink✯ \large\sf \pmb{ \pink{ With \: Explanation}}$
$\large\blue✯ \large\sf \pmb{ \blue {No \: copied \: answer} }$
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Answer 1

A student took the least count of a vernier calliper as 0.01 mm instead of 0.01 cm and found that the length of a copper rod was 4.909 cm. If one M.S.D. = 1 mm, then find

1) the main scale reading

2) the vernier coinciding division

3) the correct length of the rod

answer in the attachment

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Answer 2

Answer:

$\color{darkcyan} \underline{ \begin{array}{ || |l| || } \hline \color{magenta} \\ \hline \boxed{ \text{ \tt \: Solution:-} } \end{array}}$

Explanation:

The value of 1 M.S.D. =1 mm (given)

The correct least count of vernier calliper is 0.01 cm .

Then what is the formula of the least count

$\text{ \( \rm \left( L.C.=\dfrac{1 \text { M.S.D. }}{ N }\right) \)}$

How many divisions are present on the vernier scale? The formula for the length of a vernier calipers is

$\text{\( \ell= \) M.S.R. + V.C. \( \times \) L.C. \qquad- - - (1)}$

Is the value measured by the student a mistake?

What is its value?

Then, the value of MSR is =4.9 cm.

Then, what is the value of V.C.D.?

⟹ By inserting the values of M.S.R., V.C.D. and L.C. in (1), the correct length of the rod is obtained. M.S.R. =49 mm, V.C.D. =9, Original reading = 49.9 mm.