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The given function g(x) is defined at all integral points.
Let n be an integer.
Then g(n)=n−n=n−n=0
L.H.L. at x=n=lim
x→n
−
g(x)=lim
x→n
−
(x−[x])=n−(n−1)=1
R.H.L. at x=n=lim
x→n
+
g(x)=lim
x→n
+
(x−[x])=n−n=0
Since L.H.L.
=R.H.L.
Therefore g is not continuous at x=n. i.e.,
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Answer:
Any function f(x) will be discontinuous at x -values that make the function undefined. Here, that will simply be any x -value that creates a "division by zero". So division by zero occurs when x=±3 .
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