Question

$\large{\underline{\underline{\text{\purple{Question: - }}}}}$
$\\ \sf{Prove \: that : - }$
$\sf{\bold{{m}_{1}{u}_{1} + {m}_{2}{u}_{2}= {{m}_{1}{v}_{1} + {m}_{2}{v}_{2}}}}$
$\\ \tt{\checkmark{\red{Quality \: answer \: needed!!}}}$
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Answer 1

$solution:—$

$=>f_{1} = - f_{2} \\=> m_{2}a_{2} = - m_{1}a_{1} \\ =>m_{2} \frac{u_{2} -v_{2}}{t} = - m_{1}( \frac{u_{1} -v_{1}}{t} )$

$=>\: m_{2}u_{2} - m_{2}v_{2} = m_{1}u_{1} - m_{1}v_{1}$

$=>\: m_{1}u_{1} + m_{2}v_{2} = m_{1}v_{1} + m_{2}u_{2}$

$=>\: momentum \: before \: collison = momentum \: after \: collison$

$hence \: proved.$

$hello \: faizal \: nuha \: my \: previous \: id \: ritamriyu123 \: i \: have \: deleted \:$

$it \: is \: the \: new \: id$

Answer 2

Answer:

=> f1= -f2

=> m2a2 = -m1a1

=>m2 * (u2 - v2)/t = m1*(u1 - v1) /t

=> m2u2 - m2v2 = m1u1 - m1v1

=> -m1u1 - m2v2 = - m1v1 -m2u2

=> m1u1 + m2v2 = m1v1 + m2u2

Hence proved

Explanation:

Hi Faizalnuha ☺