Math, asked by Anonymous, 3 months ago

\left[\begin{array}{ccc}4\\1\\\end{array}\right]X=\left[\begin{array}{ccc}-4&8\\-1&2\\\end{array}\right]
Find the value of X .​

Answers

Answered by Anonymous
1

Answer:

\underline{\bigstar\:\textsf{According to the given Question :}}

:\implies\sf X=\left[\begin{array}{cc}-4&8\\-1&2\\\end{array}\right]\\\\\\:\implies\sf X = [( - 4) \times 2] - [8 \times ( - 1)]\\\\\\:\implies\sf X = - 8 - ( - 8)\\\\\\:\implies\sf X =  - 8 + 8\\\\\\:\implies\sf X = 0

\therefore\:\underline{\textsf{Hence, the value of X is equal to \textbf{0}}}.

Answered by chimkandi525
3

Answer:

According to the given Question :

\begin{gathered}:\implies\sf X=\left[\begin{array}{cc}-4&8\\-1&2\\\end{array}\right]\\\\\\:\implies\sf X = [( - 4) \times 2] - [8 \times ( - 1)]\\\\\\:\implies\sf X = - 8 - ( - 8)\\\\\\:\implies\sf X = - 8 + 8\\\\\\:\implies\sf X = 0\end{gathered}

:⟹X=[

−4

−1

8

2

]

:⟹X=[(−4)×2]−[8×(−1)]

:⟹X=−8−(−8)

:⟹X=−8+8

:⟹X=0

\therefore\:\underline{\textsf{Hence, the value of X is equal to \textbf{0}}}.∴

Hence, the value of X is equal to 0

.

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